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Proof step 18 from proof unchanged-getbar (conclusion)

⊦ getbytearray(r, st) ≠ getbytearray(r, st0) ∧ okbytearray(r, st) → ¬ unchanged(str, r, st, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
okbytearray(r, st), unchanged(str, r, st, st0) ⊦ getbytearray(r, st) = getbytearray(r, st0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]