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Proof step 13 from proof unchanged-junkref-level (conclusion)

⊦ unchanged(str0, r, st, st1) ∧ junkref(str, r, st) ∧ level⊆(str, str0) → junkref(str, r, st1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
level⊆(str, str0), junkref(str, r, st), unchanged(str0, r, st, st1) ⊦ junkref(str, r, st1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]