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Proof step 9 from proof unchanged-junkref-level (previous step)

refs = r + refs0, level⊆(str, str0), junkrefs(str, refs, st[r -- _type] .type, st), unchanged(str0, r, st, st1) ⊦ refs = [], junkref(str, r, st1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
unchanged(str0, r, st, st1), level⊆(str, str0), junkrefs(str, r ' + refs0, st[r -- _type] .type, st) ⊦ junkref(str, r, st1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : list, references, a, ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPNAMEDSEQ : list, references, e-01, ⊦ r ' + refs ≠ []], [CSIMPNAMEDSEQ : list, references, c, ⊦ r + refs = r ' + refs])]]