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Proof step 10 from proof unchanged-levelsubset-equiv (previous step)

¬ (unchanged(str0, r, st0, st) ∧ junkref(str, r, st0) ∧ level⊆(str, str0)), path∃(str, r, r0, st) ↔ path∃(str0, r, r0, st0), level⊆(str, str0), unchanged(str0, r, st, st0), junkref(str, r, st0), ∀ r0. (path∃(str0, r, r0, st) ↔ path∃(str0, r, r0, st0)) ∧ (path∃(str0, r, r0, st) → unchangedNorec(r0, st, st0)), path∃(str0, r, r0, st0) → unchangedNorec(r0, st, st0) ⊦ path∃(str0, r, r0, st0) ↔ path∃(str, r, r0, st0), junkref(str, r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
path∃(str, r, r0, st) ↔ path∃(str0, r, r0, st0), level⊆(str, str0), unchanged(str0, r, st, st0), junkref(str, r, st0), ∀ r0. (path∃(str0, r, r0, st) ↔ path∃(str0, r, r0, st0)) ∧ (path∃(str0, r, r0, st) → unchangedNorec(r0, st, st0)), path∃(str0, r, r0, st0) → unchangedNorec(r0, st, st0) ⊦ path∃(str0, r, r0, st0) ↔ path∃(str, r, r0, st0), junkref(str, r, st), unchanged(str0, r, st0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]