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Proof step 5 from proof unchanged-okbar (previous step)

unchanged(str, r, st, st0) ∧ path∃(str, r, r1, st) → unchanged(str, r1, st, st0), okbytearray(r1, st), path∃(str, r, r1, st), unchanged(str, r, st, st0) ⊦ okbytearray(r1, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
okbytearray(r1, st), path∃(str, r, r1, st), unchanged(str, r, st, st0), unchanged(str, r1, st, st0) ⊦ okbytearray(r1, st0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]