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Proof step 15 from proof unchanged-pathex-append (previous step)

∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = r0 ∧ validrefs(str, refs, mkclasstype(`java.lang.Object' .class), st), unchanged(str, r, st, st1), validrefs(str, r0 ' + refs0, mkclasstype(`java.lang.Object' .class), st), r1 = r0 ∨ r1 ∈ refs0 ⊦ path∃(str, r0, (r0 ' + refs0) .last, st1), unchangedNorec(r1, st, st1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
validrefs(str, refs, mkclasstype(`java.lang.Object' .class), st), unchanged(str, refs .first, st, st1), validrefs(str, refs .last ' + refs0, mkclasstype(`java.lang.Object' .class), st), r1 = refs .last ∨ r1 ∈ refs0 ⊦ refs = [], path∃(str, refs .last, (refs .last ' + refs0) .last, st1), unchangedNorec(r1, st, st1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]