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Proof step 21 from proof unchanged-pathex-append (previous step)

∃ refs. refs ≠ [] ∧ refs .first = r0 ∧ refs .last = r1 ∧ validrefs(str, refs, mkclasstype(`java.lang.Object' .class), st), path∃(str, r, r0, st), unchanged(str, r, st, st1) ⊦ path∃(str, r0, r1, st1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
validrefs(str, refs, mkclasstype(`java.lang.Object' .class), st), path∃(str, r, refs .first, st), unchanged(str, r, st, st1) ⊦ refs = [], path∃(str, refs .first, refs .last, st1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]