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Proof step 23 from proof unchanged-pathex-append (conclusion)

⊦ unchanged(str, r, st, st1) ∧ path∃(str, r, r0, st) ∧ path∃(str, r0, r1, st) → path∃(str, r0, r1, st1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
path∃(str, r0, r1, st), path∃(str, r, r0, st), unchanged(str, r, st, st1) ⊦ path∃(str, r0, r1, st1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]