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Proof step 2 from proof unchanged-pathex-unchNorec (previous step)

path∃(str, r, r0, st), ∀ r0. (path∃(str, r, r0, st) ↔ path∃(str, r, r0, st0)) ∧ (path∃(str, r, r0, st) → unchangedNorec(r0, st, st0)) ⊦ unchangedNorec(r0, st, st0)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 2, [QUANTTERMLIST : (r0)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r0)]]