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Proof step 15 from proof unchanged-pathex-unchanged (previous step)

path∃(str, r, r1, st) ↔ path∃(str, r, r1, st1), path∃(str, r, r0, st), unchanged(str, r, st, st1), path∃(str, r, r1, st1) → unchangedNorec(r1, st, st1), ∀ r0. (path∃(str, r, r0, st) ↔ path∃(str, r, r0, st1)) ∧ (path∃(str, r, r0, st) → unchangedNorec(r0, st, st1)) ⊦ path∃(str, r0, r1, st) → unchangedNorec(r1, st, st1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]