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Proof step 22 from proof unchanged-pathex-unchanged (previous step)

path∃(str, r, r0, st), unchanged(str, r, st, st1) ⊦ unchanged(str, r0, st, st1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ unchanged(str, r, st, st0) ↔ (∀ r0. (path∃(str, r, r0, st) ↔ path∃(str, r, r0, st0)) ∧ (path∃(str, r, r0, st) → unchangedNorec(r0, st, st0)))
Proof step 21:
path∃(str, r, r0, st), unchanged(str, r, st, st1) ⊦ ∀ r1. (path∃(str, r0, r1, st) ↔ path∃(str, r0, r1, st1)) ∧ (path∃(str, r0, r1, st) → unchangedNorec(r1, st, st1))

Rule argument

[x0lemmaarg: spec-name: instance-name: lemma-name: unchanged-def antecedent: succedent: unchanged(str, r, st, st0) ↔ (∀ r0. (path∃(str, r, r0, st) ↔ path∃(str, r, r0, st0)) ∧ (path∃(str, r, r0, st) → unchangedNorec(r0, st, st0))) substlist: [st0, st, r, str] → [st1, st, r0, str] add preconditions?: F is rewrite lemma?: T current spec?: T rotate lemma?: F replace all?: T paths: ((1, 0, 0)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st1, st, r0, str)]]