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Proof step 15 from proof unchanged-pathex (previous step)

∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = r0 ∧ validrefs(str, refs, mkclasstype(`java.lang.Object' .class), st), unchanged(str, r, st, st1) ⊦ ∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = r0 ∧ validrefs(str, refs, mkclasstype(`java.lang.Object' .class), st1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
validrefs(str, refs, mkclasstype(`java.lang.Object' .class), st), unchanged(str, refs .first, st, st1) ⊦ refs = [], ∃ refs0. refs0 ≠ [] ∧ refs0 .first = refs .first ∧ refs0 .last = refs .last ∧ validrefs(str, refs0, mkclasstype(`java.lang.Object' .class), st1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]