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Proof step 18 from proof unchanged-pathex (conclusion)

⊦ unchanged(str, r, st, st1) ∧ path∃(str, r, r0, st) → path∃(str, r, r0, st1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
path∃(str, r, r0, st), unchanged(str, r, st, st1) ⊦ path∃(str, r, r0, st1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]