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Proof step 11 from proof unchanged-symmetric (previous step)

∀ r0. (path∃(str, r, r0, st1) ↔ path∃(str, r, r0, st)) ∧ (path∃(str, r, r0, st1) → unchangedNorec(r0, st1, st)) ⊦ (path∃(str, r, r0, st) ↔ path∃(str, r, r0, st1)) ∧ (path∃(str, r, r0, st) → unchangedNorec(r0, st, st1))

User applied rule all left

And obtained the following new goals

Proof step 10:
(path∃(str, r, r0, st1) ↔ path∃(str, r, r0, st)) ∧ (path∃(str, r, r0, st1) → unchangedNorec(r0, st1, st)) ⊦ (path∃(str, r, r0, st) ↔ path∃(str, r, r0, st1)) ∧ (path∃(str, r, r0, st) → unchangedNorec(r0, st, st1))

Rule argument

[EXRARG : pos: left 1, [extquanttermlist: (r0)abort:F, discard:T, computed:T]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r0)]]