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Proof step 3 from proof seq (conclusion)

⊦ ¬ r0 < r → (¬ r < r0 ↔ r = r0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ r = r0, r0 < r, r < r0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]