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Proof step 58 from proof addarray-disjoint-nosharing-01 (previous step)

vals[i→n(i0)] = refval(r1), st[r1 -- sks] = refval(r0), st[r1 -- sks1] = refval(r0), r1 -- sks ∈ st, st ⊆ addarray(r, ty, vals, st), is_referencevalue(addarray(r, ty, vals, st)[r -- (i0 ' ' + sks)]), fits(r1, sks, st), fits(r1, sks1, st), 0 ≤ i0, disjoint(str, vals .nonnullrefs, st), validreflist(str, vals, ty, st), newref(r, st), i0 < n→i(# vals), is_referencevalue(addarray(r, ty, vals, st)[r -- (i0 ' ' + sks1)]), r1 -- sks1 ∈ st ⊦ r = jvmref, vals = [], r0 = jvmref, sks = sks1, dups(vals .nonnullrefs), ∃ r. r ∈ vals .nonnullrefs ∧ hasSharing(r, st), junkref(str, r1, st)

User applied rule exists right

And obtained the following new goals

Proof step 57:
vals[i→n(i0)] = refval(r1), st[r1 -- sks] = refval(r0), st[r1 -- sks1] = refval(r0), r1 -- sks ∈ st, st ⊆ addarray(r, ty, vals, st), is_referencevalue(addarray(r, ty, vals, st)[r -- (i0 ' ' + sks)]), fits(r1, sks, st), fits(r1, sks1, st), 0 ≤ i0, disjoint(str, vals .nonnullrefs, st), validreflist(str, vals, ty, st), newref(r, st), i0 < n→i(# vals), is_referencevalue(addarray(r, ty, vals, st)[r -- (i0 ' ' + sks1)]), r1 -- sks1 ∈ st ⊦ r = jvmref, vals = [], r0 = jvmref, sks = sks1, dups(vals .nonnullrefs), r1 ∈ vals .nonnullrefs ∧ hasSharing(r1, st), junkref(str, r1, st)

Rule argument

[EXRARG : pos: right 6, [extquanttermlist: (r1)abort:F, discard:T, computed:F]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r1)]]