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Proof step 111 from proof addarray-disjoint-nosharing (previous step)

(addarray(r, ty, mkjavavalues(refs), st)[r -- sks]) = refval(r0) ∧ is_referencevalue(addarray(r, ty, mkjavavalues(refs), st)[r -- sks]), (addarray(r, ty, mkjavavalues(refs), st)[r -- sks0]) = (addarray(r, ty, mkjavavalues(refs), st)[r -- sks]), fits(r, sks0, addarray(r, ty, mkjavavalues(refs), st)), fits(r, sks, addarray(r, ty, mkjavavalues(refs), st)), disjoint(str, refs, st), validreflist(str, mkjavavalues(refs), ty, st), newref(r, st) ⊦ r = jvmref, r0 = jvmref, sks = [], sks0 = [], sks0 = sks, dups(refs), hasSharing(refs, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 110:
(addarray(r, ty, mkjavavalues(refs), st)[r -- sks0]) = refval(r0), (addarray(r, ty, mkjavavalues(refs), st)[r -- sks]) = refval(r0), newref(r, st), validreflist(str, mkjavavalues(refs), ty, st), disjoint(str, refs, st), fits(r, sks, addarray(r, ty, mkjavavalues(refs), st)), fits(r, sks0, addarray(r, ty, mkjavavalues(refs), st)) ⊦ sks0 = sks, sks0 = [], sks = [], r0 = jvmref, r = jvmref, hasSharing(refs, st), dups(refs)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ is_referencevalue(refval(r))])]]