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Proof step 113 from proof addarray-disjoint-nosharing (previous step)

∃ sks1, sks2. fits(r, sks1, addarray(r, ty, mkjavavalues(refs), st)) ∧ fits(r, sks2, addarray(r, ty, mkjavavalues(refs), st)) ∧ sks1 ≠ sks2 ∧ sks1 ≠ [] ∧ sks2 ≠ [] ∧ (addarray(r, ty, mkjavavalues(refs), st)[r -- sks1]) .refval ≠ jvmref ∧ (addarray(r, ty, mkjavavalues(refs), st)[r -- sks1]) = (addarray(r, ty, mkjavavalues(refs), st)[r -- sks2]), disjoint(str, refs, st), validreflist(str, mkjavavalues(refs), ty, st), newref(r, st) ⊦ r = jvmref, dups(refs), hasSharing(refs, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 112:
(addarray(r, ty, mkjavavalues(refs), st)[r -- sks0]) = (addarray(r, ty, mkjavavalues(refs), st)[r -- sks]), fits(r, sks0, addarray(r, ty, mkjavavalues(refs), st)), fits(r, sks, addarray(r, ty, mkjavavalues(refs), st)), disjoint(str, refs, st), validreflist(str, mkjavavalues(refs), ty, st), newref(r, st) ⊦ r = jvmref, (addarray(r, ty, mkjavavalues(refs), st)[r -- sks]) .refval = jvmref, sks = [], sks0 = [], sks0 = sks, dups(refs), hasSharing(refs, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]