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Proof step 25 from proof addarray-disjoint-nosharing (previous step)

¬ (st ⊆ addarray(r, ty, mkjavavalues(refs), st) ∧ ¬ junkref(str, refs[i→n(i0)], st)), (addarray(r, ty, mkjavavalues(refs), st)[refs[i→n(i0)] -- sks]) = refval(r0), (addarray(r, ty, mkjavavalues(refs), st)[refs[i→n(i)] -- sks1]) = refval(r0), is_referencevalue(addarray(r, ty, mkjavavalues(refs), st)[r -- (i ' ' + sks1)]), is_referencevalue(addarray(r, ty, mkjavavalues(refs), st)[r -- (i0 ' ' + sks)]), i→n(i) < # refs, 0 ≤ i0, fits(refs[i→n(i0)], sks, addarray(r, ty, mkjavavalues(refs), st)), fits(refs[i→n(i)], sks1, addarray(r, ty, mkjavavalues(refs), st)), disjoint(str, refs, st), validreflist(str, mkjavavalues(refs), ty, st), newref(r, st), 0 ≤ i, i→n(i0) < # refs, i0 < n→i(# refs), i < n→i(# refs) ⊦ i0 ' ' + sks = i ' ' + sks1, r = jvmref, refs = [], r0 = jvmref, dups(refs), hasSharing(refs, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ newref(r, st) → ( ¬ st ⊆ addarray(r, ty, vals, st) ↔ false)])]]