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Proof step 31 from proof addarray-disjoint-nosharing (previous step)

(addarray(r, ty, mkjavavalues(refs), st)[refs[i→n(i)] -- sks1]) = refval(r0), (addarray(r, ty, mkjavavalues(refs), st)[refs[i→n(i0)] -- sks]) = refval(r0), i < n→i(# refs), i0 < n→i(# refs), i→n(i0) < # refs, 0 ≤ i, newref(r, st), ∀ val. val ∈ mkjavavalues(refs) → is_referencevalue(val) ∧ validref(str, val .refval, ty, st), disjoint(str, refs, st), fits(refs[i→n(i)], sks1, addarray(r, ty, mkjavavalues(refs), st)), fits(refs[i→n(i0)], sks, st), 0 ≤ i0, i→n(i) < # refs, is_referencevalue(addarray(r, ty, mkjavavalues(refs), st)[r -- (i0 ' ' + sks)]), is_referencevalue(addarray(r, ty, mkjavavalues(refs), st)[r -- (i ' ' + sks1)]), st ⊆ addarray(r, ty, mkjavavalues(refs), st), junkref(str, refs[i→n(i)], st) ⊦ r0 = jvmref, refs = [], r = jvmref, i0 ' ' + sks = i ' ' + sks1, junkref(str, refs[i→n(i0)], st), hasSharing(refs, st), dups(refs)

User applied rule all left

And obtained the following new goals

Proof step 30:
(addarray(r, ty, mkjavavalues(refs), st)[refs[i→n(i)] -- sks1]) = refval(r0), (addarray(r, ty, mkjavavalues(refs), st)[refs[i→n(i0)] -- sks]) = refval(r0), i < n→i(# refs), i0 < n→i(# refs), i→n(i0) < # refs, 0 ≤ i, newref(r, st), refval(refs[i→n(i)]) ∈ mkjavavalues(refs) → is_referencevalue(refval(refs[i→n(i)])) ∧ validref(str, refval(refs[i→n(i)]) .refval, ty, st), disjoint(str, refs, st), fits(refs[i→n(i)], sks1, addarray(r, ty, mkjavavalues(refs), st)), fits(refs[i→n(i0)], sks, st), 0 ≤ i0, i→n(i) < # refs, is_referencevalue(addarray(r, ty, mkjavavalues(refs), st)[r -- (i0 ' ' + sks)]), is_referencevalue(addarray(r, ty, mkjavavalues(refs), st)[r -- (i ' ' + sks1)]), st ⊆ addarray(r, ty, mkjavavalues(refs), st), junkref(str, refs[i→n(i)], st) ⊦ r0 = jvmref, refs = [], r = jvmref, i0 ' ' + sks = i ' ' + sks1, junkref(str, refs[i→n(i0)], st), hasSharing(refs, st), dups(refs)

Rule argument

[EXRARG : pos: left 8, [extquanttermlist: (refval(refs[i→n(i)])) abort:F , discard:T , computed:F ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (refval(refs[i→n(i)]))]]