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Proof step 10 from proof disjoint-def-fits (
previous step
)
¬ junkref(str, r, st), fits(r, sks, st) ⊦ ∃ refs. validrefs(str, r ' + refs, st[r -- _type] .type, st) ∧ st[r -- sks] .refval = (r ' + refs) .last
Lemma
ex-fits-validrefs