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Proof step 25 from proof disjoint-def-fits (previous step)

∀ refs0, refs1. refs0 = [] ∨ refs1 = [] ∨ ¬ refs0 .first ∈ refs ∨ ¬ refs1 .first ∈ refs ∨ refs0 .first = refs1 .first ∨ refs0 .last ≠ refs1 .last ∨ refs0 .last = jvmref ∨ ¬ validrefs(str, refs0, st[refs0 .first -- _type] .type, st) ∨ ¬ validrefs(str, refs1, st[refs1 .first -- _type] .type, st), validreflist(str, mkjavavalues(refs), mkclasstype(`java.lang.Object' .class), st) ⊦ ∀ r, sks, r0, sks0. ¬ r ∈ refs ∨ ¬ r0 ∈ refs ∨ r = r0 ∨ ¬ fits(r, sks, st) ∨ ¬ fits(r0, sks0, st) ∨ st[r -- sks] ≠ st[r0 -- sks0] ∨ st[r -- sks] .refval = jvmref

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 24:
st[r0 -- sks0] = st[r -- sks], r0 ∈ refs, r ∈ refs, fits(r0, sks0, st), fits(r, sks, st), validreflist(str, mkjavavalues(refs), mkclasstype(`java.lang.Object' .class), st), ∀ refs0, refs1. refs0 = [] ∨ refs1 = [] ∨ ¬ refs0 .first ∈ refs ∨ ¬ refs1 .first ∈ refs ∨ refs0 .first = refs1 .first ∨ refs0 .last ≠ refs1 .last ∨ refs0 .last = jvmref ∨ ¬ validrefs(str, refs0, st[refs0 .first -- _type] .type, st) ∨ ¬ validrefs(str, refs1, st[refs1 .first -- _type] .type, st) ⊦ r0 = r, st[r -- sks] .refval = jvmref

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]