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Proof step 29 from proof disjoint-def-fits (previous step)

st[r1 -- sks0] = refval(r3) ∧ is_referencevalue(st[r1 -- sks0]), (r1 ' + refs2) .last = (r2 ' + refs1) .last, st[r2 -- sks] = refval((r2 ' + refs1) .last), r3 = (r2 ' + refs1) .last, fits(r2, sks, st), validrefs(str, r2 ' + refs1, st[r2 -- _type] .type, st), validrefs(str, r1 ' + refs2, st[r1 -- _type] .type, st), r2 ∈ refs, r1 ∈ refs, validreflist(str, mkjavavalues(refs), mkclasstype(`java.lang.Object' .class), st), fits(r1, sks0, st), ∀ r, sks, r0, sks0. ¬ r ∈ refs ∨ ¬ r0 ∈ refs ∨ r = r0 ∨ ¬ fits(r, sks, st) ∨ ¬ fits(r0, sks0, st) ∨ st[r -- sks] ≠ st[r0 -- sks0] ∨ st[r -- sks] .refval = jvmref ⊦ (r2 ' + refs1) .last = jvmref, r1 = r2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 28:
st[r2 -- sks] = refval((r2 ' + refs1) .last), (r1 ' + refs2) .last = (r2 ' + refs1) .last, st[r1 -- sks0] = refval((r2 ' + refs1) .last), fits(r1, sks0, st), validreflist(str, mkjavavalues(refs), mkclasstype(`java.lang.Object' .class), st), r1 ∈ refs, r2 ∈ refs, validrefs(str, r1 ' + refs2, st[r1 -- _type] .type, st), validrefs(str, r2 ' + refs1, st[r2 -- _type] .type, st), fits(r2, sks, st), ∀ r, sks, r0, sks0. ¬ r ∈ refs ∨ ¬ r0 ∈ refs ∨ r = r0 ∨ ¬ fits(r, sks, st) ∨ ¬ fits(r0, sks0, st) ∨ st[r -- sks] ≠ st[r0 -- sks0] ∨ st[r -- sks] .refval = jvmref ⊦ r1 = r2, (r2 ' + refs1) .last = jvmref

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ is_referencevalue(refval(r))])]]