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Proof step 38 from proof disjoint-def-fits (previous step)

(r1 ' + refs2) .last = refs0 .last, validrefs(str, refs0, st[refs0 .first -- _type] .type, st), validreflist(str, mkjavavalues(refs), mkclasstype(`java.lang.Object' .class), st), r1 ∈ refs, refs0 .first ∈ refs, validrefs(str, r1 ' + refs2, st[r1 -- _type] .type, st), ∀ r, sks, r0, sks0. ¬ r ∈ refs ∨ ¬ r0 ∈ refs ∨ r = r0 ∨ ¬ fits(r, sks, st) ∨ ¬ fits(r0, sks0, st) ∨ st[r -- sks] ≠ st[r0 -- sks0] ∨ st[r -- sks] .refval = jvmref ⊦ refs0 = [], r1 = refs0 .first, refs0 .last = jvmref

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 37:
refs0 = r2 + refs1, (r1 ' + refs2) .last = refs0 .last, validrefs(str, refs0, st[r2 -- _type] .type, st), validreflist(str, mkjavavalues(refs), mkclasstype(`java.lang.Object' .class), st), r1 ∈ refs, r2 ∈ refs, validrefs(str, r1 ' + refs2, st[r1 -- _type] .type, st), ∀ r, sks, r0, sks0. ¬ r ∈ refs ∨ ¬ r0 ∈ refs ∨ r = r0 ∨ ¬ fits(r, sks, st) ∨ ¬ fits(r0, sks0, st) ∨ st[r -- sks] ≠ st[r0 -- sks0] ∨ st[r -- sks] .refval = jvmref ⊦ refs0 = [], r1 = r2, refs0 .last = jvmref

Rule argument

[x0lemmaarg: spec-name: list-data instance-name: references lemma-name: elim-list-c antecedent: refs ≠ [] succedent: r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0 substlist: [refs, r, refs0] → [refs0, r2, refs1] add preconditions?: F is rewrite lemma?: F current spec?: F rotate lemma?: T replace all?: T paths: () dummy: () ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : refs ≠ [] ⊦ r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0])], [EXTRATERMS : (refs0, r2, refs1)]]