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Proof step 44 from proof disjoint-def-fits (previous step)

validreflist(str, mkjavavalues(refs), mkclasstype(`java.lang.Object' .class), st) ⊦ disjoint(str, refs, st) ↔ (∀ r, sks, r0, sks0. ¬ r ∈ refs ∨ ¬ r0 ∈ refs ∨ r = r0 ∨ ¬ fits(r, sks, st) ∨ ¬ fits(r0, sks0, st) ∨ st[r -- sks] ≠ st[r0 -- sks0] ∨ st[r -- sks] .refval = jvmref)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[x0lemmaarg: spec-name: instance-name: lemma-name: disjoint-def antecedent: succedent: disjoint(str, refs, st) ↔ ¬ (∃ refs1, refs2. refs1 ≠ [] ∧ refs2 ≠ [] ∧ refs1 .first ∈ refs ∧ refs2 .first ∈ refs ∧ refs1 .first ≠ refs2 .first ∧ refs1 .last = refs2 .last ∧ refs1 .last ≠ jvmref ∧ validrefs (str, refs1, st[refs1 .first -- _type] .type, st) ∧ validrefs (str, refs2, st[refs2 .first -- _type] .type, st)) substlist: [st, refs, str] → [st, refs, str] add preconditions?: F is rewrite lemma?: T current spec?: T rotate lemma?: F replace all?: T paths: ((1, 0, 0, 1, 0)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, refs, str)]]