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Proof step 9 from proof disjoint-def-fits (previous step)

st[r0 -- sks0] = refval(r1), st[r -- sks] = refval(r1), validreflist(str, mkjavavalues(refs), mkclasstype(`java.lang.Object' .class), st), fits(r, sks, st), fits(r0, sks0, st), r ∈ refs, r0 ∈ refs, ∀ refs0, refs1. refs0 = [] ∨ refs1 = [] ∨ ¬ refs0 .first ∈ refs ∨ ¬ refs1 .first ∈ refs ∨ refs0 .first = refs1 .first ∨ refs0 .last ≠ refs1 .last ∨ refs0 .last = jvmref ∨ ¬ validrefs(str, refs0, st[refs0 .first -- _type] .type, st) ∨ ¬ validrefs(str, refs1, st[refs1 .first -- _type] .type, st) ⊦ ¬ junkref(str, r0, st), r1 = jvmref, r0 = r

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
st[r -- sks] = refval(r1), st[r0 -- sks0] = refval(r1), r0 ∈ refs, r ∈ refs, fits(r0, sks0, st), fits(r, sks, st), validreflist(str, mkjavavalues(refs), mkclasstype(`java.lang.Object' .class), st), junkref(str, r0, st), ∀ refs0, refs1. refs0 = [] ∨ refs1 = [] ∨ ¬ refs0 .first ∈ refs ∨ ¬ refs1 .first ∈ refs ∨ refs0 .first = refs1 .first ∨ refs0 .last ≠ refs1 .last ∨ refs0 .last = jvmref ∨ ¬ validrefs(str, refs0, st[refs0 .first -- _type] .type, st) ∨ ¬ validrefs(str, refs1, st[refs1 .first -- _type] .type, st) ⊦ r0 = r, r1 = jvmref

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]