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Proof step 22 from proof disjoint-def-pathex (previous step)

(r2 ' + refs2) .last = (r3 ' + refs1) .last, r2 ∈ refs, r3 ∈ refs, validrefs(str, r2 ' + refs2, st[r2 -- _type] .type, st), validrefs(str, r3 ' + refs1, st[r3 -- _type] .type, st), ∀ r, r0, r1. ¬ r ∈ refs ∨ ¬ r0 ∈ refs ∨ r = r0 ∨ r1 = jvmref ∨ ¬ path∃(str, r, r1, st) ∨ ¬ path∃(str, r0, r1, st) ⊦ r2 = r3, (r3 ' + refs1) .last = jvmref

User applied rule all left

And obtained the following new goals

Proof step 21:
(r2 ' + refs2) .last = (r3 ' + refs1) .last, r2 ∈ refs, r3 ∈ refs, validrefs(str, r2 ' + refs2, st[r2 -- _type] .type, st), validrefs(str, r3 ' + refs1, st[r3 -- _type] .type, st), ¬ r2 ∈ refs ∨ ¬ r3 ∈ refs ∨ r2 = r3 ∨ (r3 ' + refs1) .last = jvmref ∨ ¬ path∃(str, r2, (r3 ' + refs1) .last, st) ∨ ¬ path∃(str, r3, (r3 ' + refs1) .last, st) ⊦ r2 = r3, (r3 ' + refs1) .last = jvmref

Rule argument

[EXRARG : pos: left 6, [extquanttermlist: (r2, r3, (r3 ' + refs1) .last) abort:F , discard:T , computed:T ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r2, r3, (r3 ' + refs1) .last)]]