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Proof step 21 from proof disjoint-forward-array (previous step)

¬ r3 ∈ refs, path∃(str, r3, r0, st), path∃(str, r2, r0, st), r ∈ refs, r1 ∈ refs, i < st[r1 -- _length] .intval, is_arraytype(st[r1 -- _type] .type), 0 ≤ i, 0 < st[r1 -- _length] .intval, ∀ r4, r5, r6. ¬ r4 ∈ refs ∨ ¬ r5 ∈ refs ∨ r4 = r5 ∨ r6 = jvmref ∨ ¬ path∃(str, r4, r6, st) ∨ ¬ path∃(str, r5, r6, st), ¬ r3 ∈ refs ∨ ¬ r2 ∈ refs ⊦ r1 = jvmref, r = r1, r0 = jvmref, r3 = r2, junkref(str, r1, st), ¬ r3 ∈ refs -l r1 ∧ r3 ≠ st[r1 -- i '] .refval, ¬ r2 ∈ refs -l r1 ∧ r2 ≠ st[r1 -- i '] .refval

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
r2 ∈ refs, 0 < st[r1 -- _length] .intval, 0 ≤ i, is_arraytype(st[r1 -- _type] .type), i < st[r1 -- _length] .intval, r1 ∈ refs, r ∈ refs, path∃(str, r2, r0, st), path∃(str, st[r1 -- i '] .refval, r0, st), ∀ r4, r5, r6. ¬ r4 ∈ refs ∨ ¬ r5 ∈ refs ∨ r4 = r5 ∨ r6 = jvmref ∨ ¬ path∃(str, r4, r6, st) ∨ ¬ path∃(str, r5, r6, st) ⊦ r2 = r1, st[r1 -- i '] .refval = r2, r0 = jvmref, r = r1, r1 = jvmref, st[r1 -- i '] .refval ∈ refs -l r1, st[r1 -- i '] .refval ∈ refs, junkref(str, r1, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : list-del, references, in, ⊦ r ∈ refs ∧ r ≠ r0 → r ∈ refs -l r0], [CSIMPNAMEDFORWARD : list-del, references, in-01, ⊦ r ∈ refs -l r0 → r ∈ refs ∧ r ≠ r0])]]