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Proof step 24 from proof disjoint-forward-field (previous step)

¬ (is_obj(str, r1, st) ∧ r1 ≠ r0), st[r1 -- _type] .type = mkclasstype(class), st[r1 -- sk] = refval(r2), path∃(str, r3, r0, st), path∃(str, r2, r0, st), sk ∈ instfields(class), r1 ∈ refs, r ∈ refs, r3 ∈ refs, ∀ r4, r5, r6. ¬ r4 ∈ refs ∨ ¬ r5 ∈ refs ∨ r4 = r5 ∨ r6 = jvmref ∨ ¬ path∃(str, r4, r6, st) ∨ ¬ path∃(str, r5, r6, st) ⊦ r = r1, r1 = jvmref, r0 = jvmref, r3 = r2, r3 = r1, junkref(str, r1, st), r2 ∈ refs, r2 ∈ refs -l r1, path∃(str, r1, r0, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
st[r1 -- sk] = refval(r2), st[r1 -- _type] .type = mkclasstype(class), r3 ∈ refs, r ∈ refs, r1 ∈ refs, sk ∈ instfields(class), path∃(str, r2, r0, st), path∃(str, r3, r0, st), ∀ r4, r5, r6. ¬ r4 ∈ refs ∨ ¬ r5 ∈ refs ∨ r4 = r5 ∨ r6 = jvmref ∨ ¬ path∃(str, r4, r6, st) ∨ ¬ path∃(str, r5, r6, st) ⊦ r3 = r1, r3 = r2, r0 = jvmref, r1 = jvmref, r = r1, path∃(str, r1, r0, st), r2 ∈ refs -l r1, r2 ∈ refs, junkref(str, r1, st), is_obj(str, r1, st) ∧ r1 ≠ r0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]