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Proof step 31 from proof disjoint-forward-field (previous step)

st[r1 -- sk] = refval(r2), st[r1 -- _type] .type = mkclasstype(class), r3 ∈ refs, r ∈ refs, r1 ∈ refs, sk ∈ instfields(class), path∃(str, r2, r0, st), path∃(str, r3, r0, st), is_obj(str, r1, st), ∀ r4, r5, r6. ¬ r4 ∈ refs ∨ ¬ r5 ∈ refs ∨ r4 = r5 ∨ r6 = jvmref ∨ ¬ path∃(str, r4, r6, st) ∨ ¬ path∃(str, r5, r6, st) ⊦ r1 = r0, r3 = r1, r3 = r2, r0 = jvmref, r1 = jvmref, r = r1, r2 ∈ refs -l r1, r2 ∈ refs, junkref(str, r1, st), ∃ fs. fs ' ∈ instfields(class) ∧ is_referencevalue(st[r1 -- fs ']) ∧ st[r1 -- fs '] .refval ≠ jvmref ∧ st[st[r1 -- fs '] .refval -- _type] .type ≤ fs .type ∧ path∃(str, st[r1 -- fs '] .refval, r0, st)

User applied rule exists right

And obtained the following new goals

Proof step 30:
st[r1 -- sk] = refval(r2), st[r1 -- _type] .type = mkclasstype(class), r3 ∈ refs, r ∈ refs, r1 ∈ refs, sk ∈ instfields(class), path∃(str, r2, r0, st), path∃(str, r3, r0, st), is_obj(str, r1, st), ∀ r4, r5, r6. ¬ r4 ∈ refs ∨ ¬ r5 ∈ refs ∨ r4 = r5 ∨ r6 = jvmref ∨ ¬ path∃(str, r4, r6, st) ∨ ¬ path∃(str, r5, r6, st) ⊦ r1 = r0, r3 = r1, r3 = r2, r0 = jvmref, r1 = jvmref, r = r1, r2 ∈ refs -l r1, r2 ∈ refs, junkref(str, r1, st), sk .fs ' ∈ instfields(class) ∧ is_referencevalue(st[r1 -- sk .fs ']) ∧ st[r1 -- sk .fs '] .refval ≠ jvmref ∧ st[st[r1 -- sk .fs '] .refval -- _type] .type ≤ sk .fs .type ∧ path∃(str, st[r1 -- sk .fs '] .refval, r0, st)

Rule argument

[EXRARG : pos: right 10, [extquanttermlist: (sk .fs)abort:F, discard:T, computed:F]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sk .fs)]]