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Proof step 40 from proof disjoint-forward-field (previous step)

st[r1 -- _type] .type = mkclasstype(class), path∃(str, r3, r0, st), path∃(str, r2, r0, st), sk ∈ instfields(class), r1 ∈ refs, r ∈ refs, ¬ r3 ∈ refs ∨ ¬ r2 ∈ refs ∨ r3 = r2 ∨ r0 = jvmref ∨ ¬ path∃(str, r3, r0, st) ∨ ¬ path∃(str, r2, r0, st), ∀ r4, r5, r6. ¬ r4 ∈ refs ∨ ¬ r5 ∈ refs ∨ r4 = r5 ∨ r6 = jvmref ∨ ¬ path∃(str, r4, r6, st) ∨ ¬ path∃(str, r5, r6, st) ⊦ r = r1, r1 = jvmref, r0 = jvmref, r3 = r2, junkref(str, r1, st), ¬ r3 ∈ refs -l r1 ∧ r3 ≠ st[r1 -- sk] .refval, ¬ r2 ∈ refs -l r1 ∧ r2 ≠ st[r1 -- sk] .refval

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 39:
st[r1 -- _type] .type = mkclasstype(class), path∃(str, r3, r0, st), path∃(str, r2, r0, st), sk ∈ instfields(class), r1 ∈ refs, r ∈ refs, ∀ r4, r5, r6. ¬ r4 ∈ refs ∨ ¬ r5 ∈ refs ∨ r4 = r5 ∨ r6 = jvmref ∨ ¬ path∃(str, r4, r6, st) ∨ ¬ path∃(str, r5, r6, st), ¬ r3 ∈ refs ∨ ¬ r2 ∈ refs ⊦ r = r1, r1 = jvmref, r0 = jvmref, r3 = r2, junkref(str, r1, st), ¬ r3 ∈ refs -l r1 ∧ r3 ≠ st[r1 -- sk] .refval, ¬ r2 ∈ refs -l r1 ∧ r2 ≠ st[r1 -- sk] .refval

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]