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Proof step 43 from proof disjoint-forward-field (previous step)

st[r1 -- _type] .type = mkclasstype(class), path∃(str, r3, r0, st), path∃(str, r2, r0, st), sk ∈ instfields(class), r1 ∈ refs, r ∈ refs, disjoint(str, refs, st) ⊦ r = r1, r1 = jvmref, r0 = jvmref, r3 = r2, junkref(str, r1, st), ¬ r3 ∈ refs -l r1 ∧ r3 ≠ st[r1 -- sk] .refval, ¬ r2 ∈ refs -l r1 ∧ r2 ≠ st[r1 -- sk] .refval

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ disjoint(str, refs, st) ↔ ¬ (∃ r, r0, r1. r ∈ refs ∧ r0 ∈ refs ∧ r ≠ r0 ∧ r1 ≠ jvmref ∧ path∃(str, r, r1, st) ∧ path∃(str, r0, r1, st))
Proof step 42:
st[r1 -- _type] .type = mkclasstype(class), path∃(str, r3, r0, st), path∃(str, r2, r0, st), sk ∈ instfields(class), r1 ∈ refs, r ∈ refs, ∀ r, r0, r1. ¬ (r ∈ refs ∧ r0 ∈ refs ∧ r ≠ r0 ∧ r1 ≠ jvmref ∧ path∃(str, r, r1, st) ∧ path∃(str, r0, r1, st)) ⊦ r = r1, r1 = jvmref, r0 = jvmref, r3 = r2, junkref(str, r1, st), ¬ r3 ∈ refs -l r1 ∧ r3 ≠ st[r1 -- sk] .refval, ¬ r2 ∈ refs -l r1 ∧ r2 ≠ st[r1 -- sk] .refval

Rule argument

[x0lemmaarg: spec-name: instance-name: lemma-name: disjoint-def-pathex antecedent: succedent: disjoint(str, refs, st) ↔ ¬ (∃ r, r0, r1. r ∈ refs ∧ r0 ∈ refs ∧ r ≠ r0 ∧ r1 ≠ jvmref ∧ path∃(str, r, r1, st) ∧ path∃(str, r0, r1, st)) substlist: [st, refs, str] → [st, refs, str] add preconditions?: F is rewrite lemma?: T current spec?: T rotate lemma?: F replace all?: T paths: ((0, 0, 6)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, refs, str)]]