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Proof step 9 from proof disjoint-newref-01 (previous step)

refs = r2 + refs0, (r0 ' + refs1) .last = refs .last, validrefs(str, refs, st[r2 -- _type] .type, st), newref(r, st), validrefs(str, r0 ' + refs1, st[r0 -- _type] .type, st) ⊦ r = r1, r = jvmref, refs .last = jvmref, r0 = r2, refs = [], r0 ≠ r1 ∧ r0 ≠ r, r2 ≠ r1 ∧ r2 ≠ r

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
(r0 ' + refs1) .last = (r2 ' + refs0) .last, newref(r, st), validrefs(str, r0 ' + refs1, st[r0 -- _type] .type, st), validrefs(str, r2 ' + refs0, st[r2 -- _type] .type, st) ⊦ r0 = r2, r = r1, r = jvmref, (r2 ' + refs0) .last = jvmref, r0 ≠ r1 ∧ r0 ≠ r, r2 ≠ r1 ∧ r2 ≠ r

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ r ' + refs ≠ []], [CSIMPSEQ : ⊦ r + refs = r ' + refs])]]