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Proof step 11 from proof disjoint-newref-02 (previous step)

refs0 = r0 + refs1, refs0 .last = refs .last, validrefs(str, refs0, st[r0 -- _type] .type, st), validrefs(str, refs, st[refs .first -- _type] .type, st), newref(r, st) ⊦ r = r1, r = jvmref, refs .last = jvmref, r0 = refs .first, refs = [], refs0 = [], r0 ≠ r ∧ r0 ≠ r1, refs .first ≠ r ∧ refs .first ≠ r1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
(r0 ' + refs1) .last = refs .last, validrefs(str, refs, st[refs .first -- _type] .type, st), newref(r, st), validrefs(str, r0 ' + refs1, st[r0 -- _type] .type, st) ⊦ r = r1, r = jvmref, refs .last = jvmref, r0 = refs .first, refs = [], r0 ≠ r ∧ r0 ≠ r1, refs .first ≠ r ∧ refs .first ≠ r1

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ r ' + refs ≠ []], [CSIMPSEQ : ⊦ r + refs = r ' + refs])]]