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Proof step 8 from proof disjoint-newref-02 (previous step)

(r0 ' + refs1) .last = (r2 ' + refs0) .last, newref(r, st), validrefs(str, r0 ' + refs1, st[r0 -- _type] .type, st), validrefs(str, r2 ' + refs0, st[r2 -- _type] .type, st) ⊦ r0 = r2, r = r1, r = jvmref, (r2 ' + refs0) .last = jvmref, r0 ≠ r ∧ r0 ≠ r1, r2 ≠ r ∧ r2 ≠ r1

User applied rule case distinction

And obtained the following new goals

Proof step 4:
(r0 ' + refs1) .last = (r2 ' + refs0) .last, newref(r, st), validrefs(str, r0 ' + refs1, st[r0 -- _type] .type, st), validrefs(str, r2 ' + refs0, st[r2 -- _type] .type, st) ⊦ r0 ≠ r, r0 = r2, r = r1, r = jvmref, (r2 ' + refs0) .last = jvmref, r2 ≠ r ∧ r2 ≠ r1
Proof step 7:
(r0 ' + refs1) .last = (r2 ' + refs0) .last, newref(r, st), validrefs(str, r0 ' + refs1, st[r0 -- _type] .type, st), validrefs(str, r2 ' + refs0, st[r2 -- _type] .type, st) ⊦ r0 ≠ r1, r0 = r2, r = r1, r = jvmref, (r2 ' + refs0) .last = jvmref, r2 ≠ r ∧ r2 ≠ r1

Rule argument

[CASEDARG : pos: right 5, ()]

Additional information

[[CONCRETESIMPRULES : ()]]