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Proof step 15 from proof disjoint-newref (conclusion)
⊦ r = newref(st) ∧ r1 ≠ newref(st) → disjoint(str, r ' + r1 ', st)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 14
:
⊦ r1 = newref(st), disjoint(str, newref(st) ' + r1 ', st)
Rule argument
[emptyarg]
Additional information
[[CONCRETESIMPRULES : ()]]