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Proof step 16 from proof disjoint-nojunk-newref-subset-01 (previous step)

(r1 ' + refs1) .last = (r ' + refs0) .last, r1 -- _type ∈ st, validrefs(str, r ' + refs0, st1[r -- _type] .type, st1), validrefs(str, r1 ' + refs1, st[r1 -- _type] .type, st), newref(r, st), st ⊆ st1, r1 ∈ st ⊦ (r ' + refs0) .last = jvmref, r = jvmref, r1 = r, path∃(str, r, (r ' + refs0) .last, st1), junkref(str, r1, st), ¬ path∃(str, r, refs0 .last, st1) ∧ (r ' + refs0) .last ∈ refs0

User applied rule cut formula

And obtained the following new goals

Proof step 15:
refs0 = [], (r1 ' + refs1) .last = (r ' + refs0) .last, r1 -- _type ∈ st, validrefs(str, r ' + refs0, st1[r -- _type] .type, st1), validrefs(str, r1 ' + refs1, st[r1 -- _type] .type, st), newref(r, st), st ⊆ st1, r1 ∈ st ⊦ (r ' + refs0) .last = jvmref, r = jvmref, r1 = r, path∃(str, r, (r ' + refs0) .last, st1), junkref(str, r1, st), ¬ path∃(str, r, refs0 .last, st1) ∧ (r ' + refs0) .last ∈ refs0

Rule argument

[fma-arg: refs0 = []]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ refs ≠ [] → (r ' + refs) .last = refs .last], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ refs .last ∈ refs ↔ refs ≠ []])], [EXTRAFMAS : (refs0 = [])]]