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Proof step 43 from proof disjoint-nojunk-newref-subset-01 (previous step)

(r1 ' + refs0) .last = (r ' + refs1) .last, newref((r ' + refs1) .last, st), r1 -- _type ∈ st, validrefs(str, r1 ' + refs0, st[r1 -- _type] .type, st), validrefs(str, r ' + refs1, st1[r -- _type] .type, st1), newref(r, st), st ⊆ st1, r1 ∈ st, path∃(str, r, (r ' + refs1) .last, st1) ⊦ (r ' + refs1) .last = jvmref, r = jvmref, r = r1, junkref(str, r1, st)

User applied rule cut formula

And obtained the following new goals

Proof step 42:
junkref(str, (r1 ' + refs0) .last, st), (r1 ' + refs0) .last = (r ' + refs1) .last, newref((r ' + refs1) .last, st), r1 -- _type ∈ st, validrefs(str, r1 ' + refs0, st[r1 -- _type] .type, st), validrefs(str, r ' + refs1, st1[r -- _type] .type, st1), newref(r, st), st ⊆ st1, r1 ∈ st, path∃(str, r, (r ' + refs1) .last, st1) ⊦ (r ' + refs1) .last = jvmref, r = jvmref, r = r1, junkref(str, r1, st)

Rule argument

[fma-arg: junkref(str, (r1 ' + refs0) .last, st)]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ newref(r, st) → junkref(str, r, st)])], [EXTRAFMAS : (junkref(str, (r1 ' + refs0) .last, st))]]