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Proof step 59 from proof disjoint-nojunk-newref-subset-01 (previous step)

(r ' + refs1) .last = (r1 ' + refs0) .last, r1 ∈ st, st ⊆ st1, newref(r, st), validrefs(str, r ' + refs1, st1[r -- _type] .type, st1), validrefs(str, r1 ' + refs0, st[r1 -- _type] .type, st1), r1 -- _type ∈ st, path∃(str, r, (r1 ' + refs0) .last, st1) → newref((r1 ' + refs0) .last, st) ⊦ r = r1, r = jvmref, (r1 ' + refs0) .last = jvmref, junkref(str, r1, st)

User applied rule flip equation

And obtained the following new goals

Proof step 58:
(r1 ' + refs0) .last = (r ' + refs1) .last, r1 ∈ st, st ⊆ st1, newref(r, st), validrefs(str, r ' + refs1, st1[r -- _type] .type, st1), validrefs(str, r1 ' + refs0, st[r1 -- _type] .type, st1), r1 -- _type ∈ st, path∃(str, r, (r1 ' + refs0) .last, st1) → newref((r1 ' + refs0) .last, st) ⊦ r = r1, r = jvmref, (r1 ' + refs0) .last = jvmref, junkref(str, r1, st)

Rule argument

[fmapos-arg: pos: left 1]

Additional information

[[CONCRETESIMPRULES : ()]]