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Proof step 61 from proof disjoint-nojunk-newref-subset-01 (previous step)

(r ' + refs1) .last = (r1 ' + refs0) .last, r1 -- _type ∈ st, validrefs(str, r1 ' + refs0, st[r1 -- _type] .type, st1), validrefs(str, r ' + refs1, st1[r -- _type] .type, st1), newref(r, st), st ⊆ st1, r1 ∈ st, ∀ r0. path∃(str, r, r0, st1) → newref(r0, st) ∨ r0 = jvmref ⊦ (r1 ' + refs0) .last = jvmref, r = jvmref, r = r1, junkref(str, r1, st)

User applied rule all left

And obtained the following new goals

Proof step 60:
(r ' + refs1) .last = (r1 ' + refs0) .last, r1 -- _type ∈ st, validrefs(str, r1 ' + refs0, st[r1 -- _type] .type, st1), validrefs(str, r ' + refs1, st1[r -- _type] .type, st1), newref(r, st), st ⊆ st1, r1 ∈ st, path∃(str, r, (r ' + refs1) .last, st1) → newref((r ' + refs1) .last, st) ∨ (r ' + refs1) .last = jvmref ⊦ (r1 ' + refs0) .last = jvmref, r = jvmref, r = r1, junkref(str, r1, st)

Rule argument

[EXRARG : pos: left 8, [extquanttermlist: ((r ' + refs1) .last) abort:F , discard:T , computed:F ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : ((r ' + refs1) .last)]]