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Proof step 68 from proof disjoint-nojunk-newref-subset (previous step)

refs0 = r2 + refs1, refs0 .last = refs .last, validrefs(str, refs0, st1[r2 -- _type] .type, st1), validrefs(str, refs, st1[refs .first -- _type] .type, st1), st ⊆ st1, newref(r, st), ∀ r0. path∃(str, r, r0, st1) → newref(r0, st) ∨ r0 = jvmref ⊦ r = jvmref, refs .last = jvmref, r2 = refs .first, refs = [], refs0 = [], junkref(str, r1, st), r2 ≠ r ∧ r2 ≠ r1, refs .first ≠ r ∧ refs .first ≠ r1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 67:
(r2 ' + refs1) .last = refs .last, validrefs(str, refs, st1[refs .first -- _type] .type, st1), st ⊆ st1, newref(r, st), validrefs(str, r2 ' + refs1, st1[r2 -- _type] .type, st1), ∀ r0. path∃(str, r, r0, st1) → newref(r0, st) ∨ r0 = jvmref ⊦ r = jvmref, refs .last = jvmref, r2 = refs .first, refs = [], junkref(str, r1, st), r2 ≠ r ∧ r2 ≠ r1, refs .first ≠ r ∧ refs .first ≠ r1

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ r ' + refs ≠ []], [CSIMPSEQ : ⊦ r + refs = r ' + refs])]]