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Proof step 5 from proof disjoint-nopathex-same (conclusion)

⊦ disjoint(str, r ' + r0 ', st) ∧ r ≠ r0 ∧ r ≠ jvmref ∧ r0 ≠ jvmref → ¬ path∃(str, r, r0, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
disjoint(str, r ' + r0 ', st), path∃(str, r, r0, st) ⊦ r = r0, r = jvmref, r0 = jvmref

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]