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Proof step 4 from proof disjoint-nopathex (previous step)

(r0 ' + refs3) .last = (r ' + refs2) .last, validrefs(str, r ' + refs2, st[r -- _type] .type, st), validrefs(str, r0 ' + refs3, st[r0 -- _type] .type, st), ∀ refs1, refs0. refs1 = [] ∨ refs0 = [] ∨ refs1 .first ≠ r ∧ refs1 .first ≠ r0 ∨ refs0 .first ≠ r ∧ refs0 .first ≠ r0 ∨ refs1 .first = refs0 .first ∨ refs1 .last ≠ refs0 .last ∨ refs1 .last = jvmref ∨ ¬ validrefs(str, refs1, st[refs1 .first -- _type] .type, st) ∨ ¬ validrefs(str, refs0, st[refs0 .first -- _type] .type, st) ⊦ r = r0, (r ' + refs2) .last = jvmref

User applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 4, [extquanttermlist: (r0 ' + refs3, r ' + refs2) abort:F , discard:T , computed:F ]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ refs + refs0 ≠ [] ↔ refs = [] ∧ refs0 = []], [CSIMPSEQ : ⊦ r ' ≠ []], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ (r ' + refs) .first = r])], [EXTRATERMS : (r0 ' + refs3, r ' + refs2)]]