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Proof step 14 from proof disjoint-pathex-forward (previous step)

path∃(str, r4, r2, st), path∃(str, r3, r2, st), path∃(str, r, r1, st), disjoint(str, r ' + r0 ', st) ⊦ r = r0, r2 = jvmref, r4 = r3, r4 ≠ r1 ∧ r4 ≠ r0, r3 ≠ r1 ∧ r3 ≠ r0

User applied rule case distinction

And obtained the following new goals

Proof step 7:
path∃(str, r4, r2, st), path∃(str, r3, r2, st), path∃(str, r, r1, st), disjoint(str, r ' + r0 ', st) ⊦ r4 ≠ r1, r = r0, r2 = jvmref, r4 = r3, r3 ≠ r1 ∧ r3 ≠ r0
Proof step 13:
path∃(str, r4, r2, st), path∃(str, r3, r2, st), path∃(str, r, r1, st), disjoint(str, r ' + r0 ', st) ⊦ r4 ≠ r0, r = r0, r2 = jvmref, r4 = r3, r3 ≠ r1 ∧ r3 ≠ r0

Rule argument

[CASEDARG : pos: right 4, ()]

Additional information

[[CONCRETESIMPRULES : ()]]