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Proof step 5 from proof disjoint-pathex-forward (previous step)

disjoint(str, r ' + r0 ', st) ∧ path∃(str, r, r2, st) ∧ r ≠ r0 ∧ r2 ≠ jvmref → ¬ path∃(str, r0, r2, st), disjoint(str, r ' + r0 ', st), path∃(str, r, r1, st), path∃(str, r0, r2, st), path∃(str, r1, r2, st) ⊦ r1 = r0, r2 = jvmref, r = r0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
disjoint(str, r ' + r0 ', st), path∃(str, r, r1, st), path∃(str, r0, r2, st), path∃(str, r1, r2, st) ⊦ r1 = r0, r2 = jvmref, r = r0, path∃(str, r, r2, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]