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Proof step 11 from proof disjoint-symmetric (previous step)

⊦ (∀ refs, refs0. refs = [] ∨ refs0 = [] ∨ refs .first ≠ r ∧ refs .first ≠ r0 ∨ refs0 .first ≠ r ∧ refs0 .first ≠ r0 ∨ refs .first = refs0 .first ∨ refs .last ≠ refs0 .last ∨ refs .last = jvmref ∨ ¬ validrefs(str, refs, st[refs .first -- _type] .type, st) ∨ ¬ validrefs(str, refs0, st[refs0 .first -- _type] .type, st)) ↔ (∀ refs, refs0. refs = [] ∨ refs0 = [] ∨ refs .first ≠ r0 ∧ refs .first ≠ r ∨ refs0 .first ≠ r0 ∧ refs0 .first ≠ r ∨ refs .first = refs0 .first ∨ refs .last ≠ refs0 .last ∨ refs .last = jvmref ∨ ¬ validrefs(str, refs, st[refs .first -- _type] .type, st) ∨ ¬ validrefs(str, refs0, st[refs0 .first -- _type] .type, st))

User applied rule case distinction

And obtained the following new goals

Rule argument

[CASEDARG : pos: right 1, ()]

Additional information

[[CONCRETESIMPRULES : ()]]