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Proof step 9 from proof disjoint-symmetric (previous step)

refs0 .last = refs .last, validrefs(str, refs0, st[refs0 .first -- _type] .type, st), validrefs(str, refs, st[refs .first -- _type] .type, st), ∀ refs, refs0. refs = [] ∨ refs0 = [] ∨ refs .first ≠ r0 ∧ refs .first ≠ r ∨ refs0 .first ≠ r0 ∧ refs0 .first ≠ r ∨ refs .first = refs0 .first ∨ refs .last ≠ refs0 .last ∨ refs .last = jvmref ∨ ¬ validrefs(str, refs, st[refs .first -- _type] .type, st) ∨ ¬ validrefs(str, refs0, st[refs0 .first -- _type] .type, st) ⊦ refs0 = [], refs = [], refs0 .first = refs .first, refs .last = jvmref, refs0 .first ≠ r ∧ refs0 .first ≠ r0, refs .first ≠ r ∧ refs .first ≠ r0

User applied rule all left

And obtained the following new goals

Proof step 8:
refs0 .last = refs .last, validrefs(str, refs0, st[refs0 .first -- _type] .type, st), validrefs(str, refs, st[refs .first -- _type] .type, st), refs0 = [] ∨ refs = [] ∨ refs0 .first ≠ r0 ∧ refs0 .first ≠ r ∨ refs .first ≠ r0 ∧ refs .first ≠ r ∨ refs0 .first = refs .first ∨ refs0 .last ≠ refs .last ∨ refs0 .last = jvmref ∨ ¬ validrefs(str, refs0, st[refs0 .first -- _type] .type, st) ∨ ¬ validrefs(str, refs, st[refs .first -- _type] .type, st) ⊦ refs0 = [], refs = [], refs0 .first = refs .first, refs .last = jvmref, refs0 .first ≠ r ∧ refs0 .first ≠ r0, refs .first ≠ r ∧ refs .first ≠ r0

Rule argument

[EXRARG : pos: left 4, [extquanttermlist: (refs0, refs) abort:F , discard:T , computed:T ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (refs0, refs)]]