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Proof step 68 from proof ex-fits-validrefs-stronger (previous step)

st[r -- sk] = refval(r0), # refs = # sks0, is_array(str, r, st), fits(r0, sks0, st), validrefs(str, r0 ' + refs, st[r0 -- _type] .type, st), is_arraytype(st[r -- _type] .type), is_indexkey(sk), sk .index < st[r -- _length] .intval, 0 ≤ sk .index, 0 < st[r -- _length] .intval, ∀ sks1. sks1 ⊑ sks0 ∧ sks1 ≠ [] → st[r0 -- sks1] .refval = (r0 ' + refs)[# sks1] ⊦ r = jvmref, validrefs(str, r ' + r0 ' + refs, st[r -- _type] .type, st), junkref(str, r0, st), junkref(str, r, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 67:
sk = i ', st[r -- sk] = refval(r0), # refs = # sks0, is_array(str, r, st), fits(r0, sks0, st), validrefs(str, r0 ' + refs, st[r0 -- _type] .type, st), is_arraytype(st[r -- _type] .type), is_indexkey(sk), i < st[r -- _length] .intval, 0 ≤ i, 0 < st[r -- _length] .intval, ∀ sks1. sks1 ⊑ sks0 ∧ sks1 ≠ [] → st[r0 -- sks1] .refval = (r0 ' + refs)[# sks1] ⊦ r = jvmref, validrefs(str, r ' + r0 ' + refs, st[r -- _type] .type, st), junkref(str, r0, st), junkref(str, r, st)

Rule argument

[speclemmaarg: ,is_indexkey(sk) → (i = sk .index ↔ sk = i ') ,[sk, i] → [sk, i] ,T ,storekey , ,elim-04 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_indexkey(sk) → (i = sk .index ↔ sk = i ')])], [EXTRATERMS : (sk, i)]]