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Proof step 94 from proof ex-fits-validrefs-stronger (previous step)

fits(st[r -- sk] .refval, sks0, st), is_referencevalue(st[r -- sk]), ∀ r, st, str. fits(r, sks0, st) → junkref(str, r, st) ∨ (∃ refs. validrefs(str, r ' + refs, st[r -- _type] .type, st) ∧ # refs = # sks0 ∧ (∀ sks1. sks1 ⊑ sks0 ∧ sks1 ≠ [] → st[r -- sks1] .refval = (r ' + refs)[# sks1])), is_arraytype(st[r -- _type] .type) → is_indexkey(sk) ∧ 0 ≤ sk .index ∧ sk .index < st[r -- _length] .intval, is_classtype(st[r -- _type] .type) → sk ∈ instfields(st[r -- _type] .type .class) ⊦ r = jvmref, junkref(str, r, st), ∃ refs. validrefs(str, r ' + refs, st[r -- _type] .type, st) ∧ # refs = 1 + # sks0 ∧ (∀ sks. sks ⊑ sk ' + sks0 ∧ sks ≠ [] → st[r -- sks] .refval = (r ' + refs)[# sks])

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

[speclemmaarg: ,is_referencevalue(val) → (r = val .refval ↔ val = refval(r)) ,[val, r] → [st[r -- sk], r0] ,T ,javavalue , ,elim-13 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_referencevalue(val) → ( r = val .refval ↔ val = refval(r))])], [EXTRATERMS : (st[r -- sk], r0)]]