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Proof step 97 from proof ex-fits-validrefs-stronger (previous step)

∀ r, st, str. fits(r, sks0, st) → junkref(str, r, st) ∨ (∃ refs. validrefs(str, r ' + refs, st[r -- _type] .type, st) ∧ # refs = # sks0 ∧ (∀ sks1. sks1 ⊑ sks0 ∧ sks1 ≠ [] → st[r -- sks1] .refval = (r ' + refs)[# sks1])), fits(r, sk + sks0, st) ⊦ junkref(str, r, st), ∃ refs. validrefs(str, r ' + refs, st[r -- _type] .type, st) ∧ # refs = # (sk + sks0) ∧ (∀ sks1. sks1 ⊑ sk + sks0 ∧ sks1 ≠ [] → st[r -- sks1] .refval = (r ' + refs)[# sks1])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 96:
fits(r, sk ' + sks0, st), ∀ r, st, str. fits(r, sks0, st) → junkref(str, r, st) ∨ (∃ refs. validrefs(str, r ' + refs, st[r -- _type] .type, st) ∧ # refs = # sks0 ∧ (∀ sks1. sks1 ⊑ sks0 ∧ sks1 ≠ [] → st[r -- sks1] .refval = (r ' + refs)[# sks1])) ⊦ junkref(str, r, st), ∃ refs. validrefs(str, r ' + refs, st[r -- _type] .type, st) ∧ # refs = 1 + # sks0 ∧ (∀ sks. sks ⊑ sk ' + sks0 ∧ sks ≠ [] → st[r -- sks] .refval = (r ' + refs)[# sks])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (sks + sks0) + sks1 = sks + sks0 + sks1], [CSIMPSEQ : ⊦ # sk ' = 0 +1], [CSIMPSEQ : ⊦ # (sks + sks0) = # sks + # sks0], [CSIMPSEQ : ⊦ sk + sks = sk ' + sks])]]